3957 - 送分题-A+B Problem
Calculate a+b
输入
Two integer a,b (0<=a,b<=10)
输出
Output a+b
样例
输入
1 2
输出
3
提示
Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. Here is a sample solution for problem 1000 using C++/G++:
#include <iostream>
using namespace std;
int  main()
{
    int a,b;
    cin >> a >> b;
    cout << a+b << endl;
    return 0;
}
It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:
#include <stdio.h>
int main()
{
    int a,b;
    scanf("%d %d",&a, &b);
    printf("%d\n",a+b);
    return 0;
}
Here is a sample solution for problem 1000 using PASCAL:
program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end.
Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000
import java.io.*;
import java.util.*;
public class Main
{
            public static void main(String args[]) throws Exception
            {
                    Scanner cin=new Scanner(System.in);
                    int a=cin.nextInt();
                    int b=cin.nextInt();
                    System.out.println(a+b);
            }
}
Old program for jdk 1.4
import java.io.*;
import java.util.*;
public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin = 
            new BufferedReader(
                new InputStreamReader(System.in));
        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}
来源
系统原理,熟悉OJ
